How carrier is suppressed from modulating signal?
replied to: samsir
Replied to: How carrier is suppressed from modulating signal?
Hi,
If the carrier is:
v(t) = Vc * cos(Wc * t)
where
Vc is the carrier amplitude peak
Wc = 2 * PI * Fc
Fc is the carrier frequency
And let us assume a simple modulating signal as:
s(t) = Vs * cos(Ws * t)
Vs is the signal peak
Ws = 2 * PI * Fs
Fs is the signal frequency
By using a multiplier circuit as MC1496 for example (I used it for my thesis in 1979), the ouput will be:
= v(t) * s(t)
= Vc * cos(Wc * t) * Vs * cos(Ws * t)
= Vm * cos(Wc * t) * cos(Ws * t)
where Vm = Vc*Vs
= Vm/2 * {cos[(Wc+Ws)*t] + cos[(Wc-Ws)*t]}
As you see there are only two sidebands with no signal at the frequency Wc (Fc) of the carrier.
So we usually don't suppress the carrier from an AM signal. Instead, We generate the DSB-SC directly.
Kerim